60=n^2-17n

Solution for 60=n^2-17n equation:

60=n^2-17n

We move all terms to the left:

60-(n^2-17n)=0

We get rid of parentheses

-n^2+17n+60=0

We add all the numbers together, and all the variables

-1n^2+17n+60=0

a = -1; b = 17; c = +60;
Δ = b2-4ac
Δ = 172-4·(-1)·60
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*-1}=\frac{-40}{-2}
=+20
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*-1}=\frac{6}{-2}
=-3
$